chore: 修改eslintrc
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@ -9,11 +9,14 @@
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"ecmaVersion": "latest",
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"sourceType": "module"
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},
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"ignores": ["leetcode/*"],
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// "ignores": ["leetcode/*"],
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"rules": {
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"no-plusplus": "off", // 允许i++,i--
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"no-use-before-define": "off", // 无需在调用前面定义，之后定义也可以
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"no-console": "off",
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"no-continue": "off", // 允许使用continue
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"no-bitwise": "off", // 允许使用位运算
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"max-classes-per-file": "off", // 允许一个文件写多个类
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"import/extensions": [
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"error",
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"ignorePackages", // 忽略 node_modules 内的包
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@ -20,71 +20,71 @@
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解释：也就是用列表表示
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*/
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function addTwoNumbers(l1, l2) {
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const head = new ListNode()
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let curNode = head
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let carry = 0
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while (l1!==null || l2!==null) {
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let x = l1 !== null ? l1.val : 0
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let y = l2 !== null ? l2.val : 0
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let sum = x + y + carry
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curNode.val = sum % 10
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carry = Math.floor(sum/10)
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if(l1!==null) l1=l1.next
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if(l2!==null) l2=l2.next
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if(carry > 0 || l1 !=null || l2 != null){
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curNode.next = new ListNode()
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curNode = curNode.next
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}
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}
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if(carry!==0) {
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curNode.val = carry
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}
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return head
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}
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function addTwoNumbers2(l1, l2){
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const task1 = []
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const task2 = []
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while(l1 || l2) {
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if(l1){
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task1.push(l1.val)
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l1 = l1.next
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}
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if(l2){
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task2.push(l2.val)
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l2 = l2.next
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}
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}
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let target = BigInt(task1.reverse().join('')) + BigInt(task2.reverse().join(''))
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// console.log(Number(task1.reverse().join('')));
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console.log(target);
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const head = new ListNode()
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let cur = head
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while (target) {
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cur.val = target % 10n
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target = target / 10n
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cur.next = target ? new ListNode() : null
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cur = cur.next
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}
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return head
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}
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// 换一种思路，我们按照顺序压入栈中，再依次弹出，之后生成对应的数，最后再把这个数转化为链表不就行了吗？
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// 输入：l1 = [9,9,9,9,9,9,9], l2 = [9,9,9,9]
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// 输出：[8,9,9,9,0,0,0,1]
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import {LinkList, LinkListNode as ListNode} from '../../list/index.js'
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import { LinkList, LinkListNode as ListNode } from '../../list/index.js';
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const l1 = LinkList.fromArray([1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1]).head
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const l2 = LinkList.fromArray([5,6,4]).head
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function addTwoNumbers(l1, l2) {
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const head = new ListNode();
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let curNode = head;
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let carry = 0;
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while (l1 !== null || l2 !== null) {
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const x = l1 !== null ? l1.val : 0;
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const y = l2 !== null ? l2.val : 0;
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const sum = x + y + carry;
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curNode.val = sum % 10;
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carry = Math.floor(sum / 10);
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if (l1 !== null) l1 = l1.next;
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if (l2 !== null) l2 = l2.next;
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if (carry > 0 || l1 != null || l2 != null) {
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curNode.next = new ListNode();
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curNode = curNode.next;
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}
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}
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if (carry !== 0) {
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curNode.val = carry;
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}
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return head;
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}
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function addTwoNumbers2(l1, l2) {
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const task1 = [];
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const task2 = [];
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while (l1 || l2) {
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if (l1) {
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task1.push(l1.val);
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l1 = l1.next;
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}
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if (l2) {
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task2.push(l2.val);
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l2 = l2.next;
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}
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}
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let target = BigInt(task1.reverse().join('')) + BigInt(task2.reverse().join(''));
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// console.log(Number(task1.reverse().join('')));
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console.log(target);
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const head = new ListNode();
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let cur = head;
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while (target) {
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cur.val = target % 10n;
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target /= 10n;
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cur.next = target ? new ListNode() : null;
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cur = cur.next;
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}
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return head;
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}
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const l1 = LinkList.fromArray(
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[1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1],
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).head;
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const l2 = LinkList.fromArray([5, 6, 4]).head;
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// console.log(LinkList.prototype.toString.apply(addTwoNumbers(l1,l2)));
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console.log(LinkList.prototype.toString.apply(addTwoNumbers2(l1,l2)));
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console.log(LinkList.prototype.toString.apply(addTwoNumbers2(l1, l2)));
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console.log(LinkList.prototype.toString.apply(addTwoNumbers(l1, l2)));
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@ -1,7 +1,5 @@
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/* leetcode 371
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给你两个整数 a 和 b ，不使用 运算符 + 和 - ，计算并返回两整数之和。
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给你两个整数 a 和 b ，不使用 运算符 + 和 - 计算并返回两整数之和。
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示例 1：
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@ -12,7 +10,6 @@
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输入：a = 2, b = 3
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输出：5
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提示：
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-1000 <= a, b <= 1000
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@ -34,21 +31,22 @@
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补码：+5 的补码与其原码相同，即 00000101，-5 的补码是其反码加1得到的结果，即 11111011。
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*/
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var getSum = function(a, b) {
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while (b != 0) {
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const getSum = (a, b) => {
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while (b !== 0) {
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const carry = (a & b) << 1;
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a = a ^ b;
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a ^= b;
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b = carry;
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}
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return a;
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};
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var getSum2 = (a, b)=>{
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if(b===0) return a // 如果进位结果为0就结束递归
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const getSum2 = (a, b) => {
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if (b === 0) return a; // 如果进位结果为0就结束递归
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const carry = (a & b) << 1;
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const c = a ^ b;
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getSum2(c, carry)
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}
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getSum2(c, carry);
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return '';
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};
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/**
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思考：
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@ -64,7 +62,5 @@ var getSum2 = (a, b)=>{
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0 9 1 1 1 1 1
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*/
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console.log(getSum(1,0));
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console.log(getSum2(2,0));
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console.log(getSum(1, 0));
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console.log(getSum2(2, 0));
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@ -7,8 +7,8 @@ export class LinkList {
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*
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* @param {LinkListNode} head - 链表的头节点
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*/
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constructor(head){
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this.head = head
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constructor(head) {
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this.head = head;
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}
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/**
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@ -16,29 +16,29 @@ export class LinkList {
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* @param {any[]} array - 要转换的数组
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* @returns { LinkList } 按数组顺序返回的链表
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*/
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static fromArray(array){
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let n = array.length
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const head = new LinkListNode(array[0])
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const linkList = new LinkList(head)
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let curNode = head
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for(let i=1;i<n;i++){
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curNode.next = new LinkListNode(array[i])
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curNode = curNode.next
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static fromArray(array) {
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const n = array.length;
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const head = new LinkListNode(array[0]);
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const linkList = new LinkList(head);
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let curNode = head;
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for (let i = 1; i < n; i++) {
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curNode.next = new LinkListNode(array[i]);
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curNode = curNode.next;
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}
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return linkList
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return linkList;
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}
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/**
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* @description 返回序列化之后的链表 1->2->3
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*/
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toString(){
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let cur = this.head || this // 兼容节点自身遍历
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let tmpArr = []
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while(cur){
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tmpArr.push(cur.val)
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cur = cur.next
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toString() {
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let cur = this.head || this; // 兼容节点自身遍历
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const tmpArr = [];
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while (cur) {
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tmpArr.push(cur.val);
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cur = cur.next;
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}
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return tmpArr.join('->')
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return tmpArr.join('->');
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}
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}
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@ -53,8 +53,8 @@ export class LinkListNode {
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* @param {any} val - 当前节点保存的值
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* @param {LinkListNode} next - 当前节点下一个节点，默认为空
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*/
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constructor(val, next = null){
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this.val = val
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this.next = next
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constructor(val, next = null) {
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this.val = val;
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this.next = next;
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}
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}
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